The auger and pneumatic capacity problems are worked the same. The only difference is using the appropriate values in SI units.
Adding and removing of water from products uses the same equations, the difference is using units of mass instead of weight.
Problem: How much water (kg) must be removed from 1.2 metric tons (t) of grain to lower the moisture from 14.5 to 11.0%DB?
Solution: Three steps
Step one: Determine the dry mass.
= 1163.31 ... kg Step three: Subtract original and new wet mass.
( 1,000 kg \ Water (kg) = WWi - WWe = 1.2 t x --- - 1163.31 ...
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